
Kenneth S. answered 10/10/17
Tutor
4.8
(62)
Algebra II EXPERT will help you survive & prosper
No doubt you have mis-typed the measurement; should be 12"
Let flat bottom of cross-section rectangle be 12-2x and each vertical side be x in length.
Area = x(12-2x) = p(x)
p'(x) = (12-2x) + x(-2), using product rule. Setting this to zero gives x=3. So width is 6", ht. = 3"
Let flat bottom of cross-section rectangle be 12-2x and each vertical side be x in length.
Area = x(12-2x) = p(x)
p'(x) = (12-2x) + x(-2), using product rule. Setting this to zero gives x=3. So width is 6", ht. = 3"