How do I graph C=4x+300, slope 4, y intercept 300

Question

How do I graph C=4x+300, slope 4, y intercept 300

Answer 1

In this case your vertical axis is labeled C instead of y.

This makes no difference to anything.

 

Find two points.  You have one already since the y-intercept

is 300 we know the point (0, 300) is on the graph.

 

Find another point.  Plug in a value for x and solve for C

 

x        4x + 300          C

----------------------------

0       0 +300            300

-50   4(-50)+300      100

 

We now have two points:  (0, 300), (-50, 100)

As you can see, the numbers are high.  You handle this by

picking a unit separation to label the axes on that is

reasonable.  Instead of labeling your axis 0, 1, 2, 3, ...,

Use larger numbers. 

I would label the axis maybe 0, 50, 100, 150, 200, 250, 300, . . .

 

Then just plot the two points and draw the connecting line.

 

Answer 2

Plot the first point, which is the y-intercept (0, 300).  Then, use the slope and the first point to find the 2nd point.  The second point is (1, 304).  Connect these two points in a straight line all across the coordinate grid.