the lenght of a rectangle is 3cm. longer than its width. its perimeter is 56 cm. find its dimensions?

Question

please answer the question correctly.

Answer 1

Basis
Length rectangle = 3cm. longer than its width.

Rectangle perimeter = 56 cm.

find its dimensions?
P = 2L +2w
L= w + 3
P= 56

P = 2L +2w

56 = 2(w+3) +2(w)

56 = 2w +6 + 2w

4w= 56 - 6

4w = 50
w = 50/4
w = 12.5

L= 12.5 +3 = 15.5
L= 15.5

Solution:
Length= 15.5 cm
Width = 12.5 cm

Answer 2

Basis

Length _rectangle = 3cm. longer than its width.

 

Rectangle perimeter = 56 cm.

 

find its dimensions?

P = 2L +2w

L= w + 3

P= 56

 

P  = 2L +2w

 

56 = 2(w+3) +2(w)

 

56 = 2w +6  + 2w

 

4w= 56  - 6  

 

4w = 50       

w = 50/4 

w = 12.5 

 

L= 12.5 +3 = 15.5

L=  15.5

 

Solution:

Length= 15.5 cm

Width = 12.5 cm

Answer 3

length of a rectangle is 3cm longer than its width:

L = w + 3

 

perimeter is 56 cm:

2(L+w) = 56

L+w = 28

 

w + 3 + w = 28

2w + 3 = 28

2w + 25

w = 12.5 cm

 

L = w + 3 = 15.5

 

The rectangle is 15.5 cm by 12.5 cm

 

Check: Perimeter = 2(L+w) = 2(15.5 + 12.5) = 2(28) = 56 cm