Justin C. answered 09/22/17
Tutor
New to Wyzant
Experienced Professional Mathematics and Physics Tutor
This turned out to be pretty difficult, if you are in Algebra I suspect there may be a typo or this is intended to be really tough. OKAY!
Lets start by using the cofunction identity { cos(a)=sin(90-a) } to get the insides to match
Lets start by using the cofunction identity { cos(a)=sin(90-a) } to get the insides to match
I recommend always using cofunction identities when you see 90 degrees or 45 degrees in your problems
a = 45-x
sin (45+x) = cos ( 90 -(45+x) ) = cos (45-x)
sin (45+x) = cos ( 90 -(45+x) ) = cos (45-x)
Now we have:
cos(45-x) = tan(45-x)
Lets change into sines and cosines and simplify
cos(45-x) = sin(45-x)/cos(45-x)
cos2(45-x) = sin(45-x)
Theres an identity we know for cos2 lets apply it and see what we have
1-sin2(45-x) = sin(45-x)
0 = sin2(45-x) + sin(45-x) -1
This looks like the quadratic 0 = u2 + u - 1 (u = sin(45-x))
This is where the difficulty begins!
The solutions to that quadratic are [-1±sqrt(5)]/2
That means we have two options:
sin(45-x) = [-1+sqrt(5)]/2
sin(45-x) = [-1-sqrt(5)]/2 <- This one is impossible because [-1-sqrt(5)]/2 = -1.61 and sin is only between -1 and 1
SO! What we are left with is this:
sin(45-x) = [-1+sqrt(5)]/2
If we use arcsin as the inverse to reverse this equation we get:
45-x = arcsin ( [-1+sqrt(5)]/2 )
45-x = 38.17271
x = 6.82729°
I got to this point and assumed that I couldnt possibly be right but if you plug it into the original equation:
sin (45+x) = 0.7861514
tan(45-x) = 0.7861514
So there you have it
x = 6.82729°
Again if you are in Algebra, I would have to guess you misread the question or your teacher/book mistyped it. In any event, go ahead and turn this in if it made any sense to you, maybe you can get some extra credit. I could use some myself right about now. >_>