Mark M. answered 09/13/17
Tutor
5.0
(278)
Mathematics Teacher - NCLB Highly Qualified
(a)
[6 / (a + h)] - [6 / a]
[6a - 6(a + h)] / [a(a + h)
[6a - 6a - 6h] / [a2 + ah]
-6h / [a2 + ah]
(b)
[-6h / (a2 + ah)] / h
-6 / (a2 + ah)