Word problem, please help solve

Question

Chuck and Dana agree to meet in Chicago. Chuck travels 208 miles in the same time Dana travels 192 miles. If chuck's rate of speed is 4 mph more than danas, and they travel the same length of time, at what speed does chuck travel?

Answer 1

Distance = rate*time ... d=rt

Thus: t = d/r

 

If Dana's rate is r, Chuck's rate is r+4:

 

Chuck: t = 208/(r+4)

Dana: t = 192/r

 

208/(r+4)=192/r

208r = 192(r+4)

208r = 192r + 768

16r = 768

r = 768/16 = 48 mph

 

Chuck = r+4 = 52 mph