Solve 2xsquared minus 8x plus 3 = 0

Question

solve using quadratic formula

Answer 1

For an equation like ax^2 + bx + c = 0, use the quadratic formula to solve for x=(-b±v(b^2-4ac))/2a In this example: a=2, b=-8, c=3 x=(-(-8)±v((-8)^2-(4*2*3)))/(2*2) The double negative cancels, square the 8 to get 64 and multiply 4*2*3 x=(8±v(64-24))/4 x=(8±v40)/4 If you are allowed to give decimal answers, you can now just add the square root of 40 to 8 and divide by 4 and then subtract the sq. rt. of 40 from 8 and divide by 4 so you would end up with x={3.58,0.42}

Answer 2

2x^2-8x+3=0

 

x= (8+_sqrt(64-24))/4

 

x=( 8+_sqrt(40))/4

 

x=3.58

x=0.418