use the quadratiic formula

While Robert's answers are correct, he didn't find them by using the quadratic formula.

The formula is very difficult to write in this wordprocessor, but it goes like this:

t = ( - b plus or minus the square root of ( b^{2} - 4ac ) ) all over 2a

where we look at the equation as at^{2}+bt+c=0.

So in your equation, a is 63, b is -38, and c is -5.

so t = (- (-38) plus or minus the square root of (-38)^{2} - 4*63*(-5) all divided by 2*63.

-(-38) = 38 (-38)^{2} = 1444 4*63*-5 = -1260 2*63 = 126

38 = 38 1444 - (-1260) = 2704 126 = 126

38 = 38 square root of 2704 = 52 126 = 126

so t is either (38+52)/126 or (38-52)/126

which is either 5 / 7 or -1 / 9.