y = ∫y'dx = ∫(2/√x - x)dx
y = 2∫x-½dx - ∫xdx
y = 4√x - ½x2 + C
Since (2,1) lies on the curve, y = 1 when x = 2.
So, 1 = 4√2 - 2 + C
C = 3 - 4√2
y = 4√x - ½x2 + 3 - 4√2
Marcus A.
asked 09/08/17
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Marcus A.
09/08/17