Inactive Tutor answered 09/07/12
(-2/3) * b + (2/5) = (6/4) / 5
The direct mathematical approach is to see that the equation is in the form
m * b + n = k where
m = -2/3;
n = 2/5;
k = (6/4) / 5 = (3/2) / 5 = 3/10 <== I reduced the fraction to lowest terms. Let me know if you don't follow.
To solve for b, we want to isolate b to one side of the equation. The first step would be to subtract n on both sides of the equation so that you're left with only a constant multiplied by b on the left side:
m * b + n - n = k - n ==> m * b = k - n
Then, if you divide both sides of the equation by m, you've solved for b:
b = (k - n) / m
Now let's plug in the actual values of m, n, and k.
b = [(3/10) - (2/5)] / (-2/3);
b = [(3/10) - (4/10)] / (-2/3);
b = (-1/10) / (-2/3);
b = (1/10) / (2/3);
b = (1/10) * (3/2);
b = 3/20
To check our work, let's plug b = 3/20 back into our original equation and see if it's correct.
(-2/3) * b + (2/5) = (6/4) / 5
(-2/3) * (3/20) + (2/5) =? (6/4) / 5
(-2/3) * (3/20) + (2/5) = (-6/60) + (2/5) = (-1/10) + (2/5) = (-1/10) + (4/10) = 3/10 = (6/4) / 5
It works!