
Josie N.
asked 08/30/17PLEASE ANSWER ASAP
#1- Find the domain of the function: f(x)=sqrt(−5x+10)/(x^2−64)
#2- Find the domain of the function:
f(x)=−16sqrt(16x+20)+4sqrt(11−10x)
f(x)=−16sqrt(16x+20)+4sqrt(11−10x)
#3- Find the domain of the function:
f(x)=sqrt(3t−36)/(20+20t)
f(x)=sqrt(3t−36)/(20+20t)
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1 Expert Answer
Michael J. answered 08/30/17
Tutor
5
(5)
Effective High School STEM Tutor & CUNY Math Peer Leader
You know that the value under the square-root cannot be negative. Also, the denominator can never be zero.
1)
Assuming everything is under the square-root, set the following conditions:
-5x + 10 ≥ 0 or x2 - 64 > 0 1st case
and
-5x + 10 ≤ 0 or x2 - 64 < 0 2nd case
Solving for the 1st case, x ≤ 2 and x < -8 or x > 8
Solving for the 2nd case, x ≥ 2 and x > -8 and x < 8
For the 1st case domain to accept is (-∞, -8)∪[2, 8)∪(8, ∞)
Work out the 2nd case.
2)
Simply set the two arguments of the square-root greater than or equal to zero.
16x + 20 ≥ 0 and 11 - 10x ≥ 0
16x ≥ -20 -10x ≥ -11
x ≥ -1.25 x ≤ 1.1
Domain in interval [-1.25, 1.1).
Question 3 is the same as the first question.
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Tim C.
08/30/17