Length and width?

Question

Suppose that the width of a certain rectangle is 1 inch more than one-fourth of its length. The perimeter of the rectangle is 32 inches. Find the length and width of the rectangle.

Answer 1

Let L = the length

Let 1/4 L + 1 = the width

P = 2L + 2W

32 = 2L + 2(1/4 L + 1)

32 = 2L + 1/2 L + 2

32 = 5/2 L + 2

30 = 5/2 L       Multiply both sides of the equation by 2/5

12 inches = L

W = 1/4 (12) + 1

W = 3 + 1

W = 4 inches