
Nathan J. answered 01/17/13
Flexible and Adaptive Tutoring- Preparing You for the Next Step
This problem is algebraic, and we are understood to be solving for the variable "p."
I find it easier to always move the variable to where it is positive. In this case, let's move him to the right side of the tracks (=).
>> 3/4 = 9p - 3/5
Great! He's happy to be positive. Now, we have two equations with uncommon denominators who don't really agree with each other. Let's make them agree. The lowest number they both agree on (and therefore are "factors" of) is 20!
>> 15/20 = 9p - 12/20
Sweet! They agree. Now let's get those fractions to live on the same side of the tracks (=).
>> 15/20 + 12/20 = 9p
>> 27/20 = 9p
Now all we have to do, is put poor "p" into solitary confinement, and put the number 9 with the others on the other side of the tracks.
>> 27/(20•9) = p
>> 27/180 = p
The only problem is, 27/180 feels fat and could use a diet. Let's trim him down. He likes 9s!
>> 3/20 = p
OR (in other words)
ANSWER: p = 3/20
Wondering how you can switch sides in an algebraic equation? Do the opposite process. Negative numbers should be ADDED to the opposite side. Positive numbers, subtracted. Multiplied numbers, divided... and divided numbers (or fractions), multiplied.
Hope this helps!