Write the equation of a line that is perpendicular to the given line and that passes through the given point.
y + 2 =1/3 (x – 5); (–4, 3)
Write the equation of a line that is perpendicular to the given line and that passes through the given point.
y + 2 =1/3 (x – 5); (–4, 3)
The slope of the perpendicular line is the negative reciprocal of (1/3), which is -3Use point-slope form for the point (-4, 3) with slope = -3,
y - 3 = -3(x + 4) <==Answer
Comments
given line is in point-slope form, with slope = m = 1/3; line perpendicular to given line would have slope = -3/1 = -3, so that second line, in point-slope form, would be: y - 3 = -3(x - (-4)); or y - 3 = -3(x + 4)