
Kenneth S. answered 07/24/17
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Correction: at WHICH f attains its maximum... (The kind of witch you used is a broom-rider.)
lim (as x approaches 0+) of f(x) = (ln x)/x
a) The logarithm goes to -infinity and the factor 1/x goes to positive infinity so their product goes to negative infinity.
b) f(x) = x-1 ln x so f'(x) = -x-2ln x + x-1(1/x) = x-2[1 - ln x]
On the domain (0,infinity) the first factor of f' is always positive, so the critical point is where ln x = 1, so x = e is the C.P.
f(x) is positive on (0,e) and negative on (e,infinity) which means the function is increasing, then decreasing when moving from left to right toward & through the critical point. Therefore the maximum function value is when x=e
and this maximum point is (e,1/e).