
Kathy M. answered 07/20/17
Tutor
5
(13)
ANY MATH -I can break it down to the basics for you!
x=x0+v0t+(1/2)at2, solve for t
First, put it in standard form & remember that even though this equation seems like all variables, x0, v0, and a are constants represented by letters (like π - pi). x (height) depends on t (time) which are the two variables that will actually vary.
In this case, a represents gravitational pull, v0 represents initial velocity, and x0 represents initial height. I am going to change that a to g for clarity when it comes time to plug numbers into quadratic formula.
Standard form:
x = (1/2)gt2 + v0t + x0
Now identify a, b, c from y = ax2 + bx + c
to plug into quadratic formula x = [ -b ± √(b2 - 4ac) ] / [2a]
a = (1/2)g = g/2
b = v0
c = x0
Time to "plug in":
t = [ -v0 ± √(v02 - 4(g/2)(x0) ) ] / [2(g/2)] (simplify the fractions)
t = [ -v0 ± √(v02 - 2gx0 ) ] / [g] (switch the g back to an a so the original question is answered)
t = [ -v0 ± √(v02 - 2ax0 ) ] / [a]
Hope this helps!
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