Nayan K.
asked • 07/14/17In triangle ABC, tan(A-B-C)=?
Question based on trignometric ratios.
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1 Expert Answer
A+B+C=180 so that
B+C=180-A
A-B-C=A-(B+C)=A-(180-A)=2A-180
tan(x-y)=(tanx-tany)/(1+tanxtany)
tan(2A-180)=(tan2A-tan(180))/(1+tan2Atan(180))=tan2A/1-tan2A) since tan(180)=-1
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Kathy M.
07/14/17