
James F. answered 06/25/14
Tutor
5
(6)
Data Scientist and former Statistics Professor
As standard unit vectors,
e1 = (1,0,...,0)
e2 = (0,1,...,0)
...
en = (0,0,...1)
There are a couple of ways to approach this depending on how vigorous of a proof class this is. One thing to note is that (e1, e2, ...,en) form a basis for Rn. Therefore they are linearly independent.
In general, vectors e1, e2, ..., en are linearly independent if:
a1*e1 + a2*e2 + ... + an*en = (0,0,...,0) implies that a1 = a2 = ... = an = 0
Since only e1 has a non-zero number as the first entry, a1 = 0.
Since only e2 has a non-zero number as the second entry, a2 = 0.
...
Since only en has a non-zero number as the nth entry, an = 0.
Therefore e1, e2, ..., en are linearly independent.
J.T.