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solving equation

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I don't see an equation.  However, if your equation is in the form:  1x2 + bx  = 0, in order to make sure the equation is a perfect square, divide b by 2, square it, and add to both sides.
 
Example:  x2 + 6x = 0,  b = 6, b/2 = 6/2 = 3,  so (b/2)2 = 32 = 9.
 
So add 9 to both sides => x2 + 6x + 9 = 9,  and (x + 3)2 = 9.
 
Another example:  3x2 - 15x - 12 = 0;  divide by 3:  x2 - 5x - 4 = 0;  add 4: x2 - 5x = 4;
 
Take 1/2 of -5, square it, and add to both sides:  x2 - 5x + (25/4) = 4 + (25/4)
 
This becomes:  (x - (5/2))2 = (16/4) + (25/4) => (x-(5/2))2 = 41/4.
 
I hope this helps.