(2) 3y - 3x = -6

**y = 0**

**x=2**

I have done this problem several times. and can not seem to get the correct work and check.

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(1) 4y + 2x = 4

(2) 3y - 3x = -6

(2) 3y - 3x = -6

Let's solve equation (1) for x:

4y + 2x = 4

2x = 4 - 4y

x = 2 - 2y

Now let's substitute 2-2y in place of x in equation 2:

3y - 3x = -6 [Equation (2)]

3y - 3(2-2y) = -6 [Substituted 2-2y for x]

3y - 6 + 6y = -6

9y = 0

Find x:

x = 2 - 2y

x = 2 - 2(0)

Check:

4y+2x = 4

4(0)+2(2) = 4

4 = 4

3y-3x=-6

3(0)-3(2) = -6

-6 = -6

Hi Adena,

4y+2x=4......eq 1

3y-3x=-6.......eq 2

Divide eq 2 by 3, we get,

y-x=-2

adding x on both the sides,

y=x-2..........eq 3

substituting value of y in eq 1, we get,

4(x-2)+2x=4

4x-8+2x=4

6x=12

x=2

substituting value of x in eq 3, we get,

y=2-2

y=0

Check: LHS of eq 1=4y+2x=4(0)+2(2)= 4=RHS

LHS of eq 2= 3y-3x=3*0-3*2=-6 = RHS

Ans: { x=2,y=0}

Meena from Strongsville,OH

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