
Philip P. answered 05/05/14
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Effective and Patient Math Tutor
You need the following two identities for this problem:
sec(x) = 1/cos(x)
sin2x + cos2x = 1
Now let's use them in your problem:
sin(x)sec(x) = [1-cos2(x)]/sin(x)cos(x)
sin(x)/cos(x) = sin2(x)/sin(x)cos(x) [sec(x) = 1/cos(x), 1-cos2(x)=sin2(x)]
sin(x)/cos(x) = sin(x)/cos(x)
QED