Arthur D. answered 05/05/14
Tutor
4.9
(306)
Forty Year Educator: Classroom, Summer School, Substitute, Tutor
log5(7x)+log5(x)=3
log5(7x*x)=3
log5(7x2)=3
53=7x2
125=7x2
125/7=x2
17.85714=x2
√17.85714=x
4.2258=x