log

_{5}(7x)+log_{5}(x)=3log

_{5}(7x*x)=3log

_{5}(7x^{2})=35

^{3}=7x^{2}125=7x

^{2}125/7=x

^{2}17.85714=x

^{2}√17.85714=x

4.2258=x

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Saugus, MA

log_{5}(7x)+log_{5}(x)=3

log_{5}(7x*x)=3

log_{5}(7x^{2})=3

5^{3}=7x^{2}

125=7x^{2}

125/7=x^{2}

17.85714=x^{2}

√17.85714=x

4.2258=x

Miami, FL

log5(7x)+log5(x)=3 is the equation, this may be transformed to log5 (7) + log5 (x) +log5 (x) =3 =>

2 log5 (x) = 3 - log5 (7) = 3-(log10(7)/log10(5)) = 3-1.2091= 1.7909=2log5 (x) =>

log5(x) = 1.7909/2= 0.8955

log (x)/log 5 = 0.8955

log (x) = 0.8955*0.6989 = 0.6258

x = log‾^{1} 0.6258 = 4.2247

CHECK!!!!!!!!!!!!!!!!!!!!!!!!!

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