please solve

Question

2log₄(2x-3)=4

Answer 1

Another approach:  2log₄(2x-3)=4.  Divide by 2: log₄(2x-3)=2.

 

Write in exponential form:  log₄(2x-3)=2  becomes 4²=2x-3.

 

solve:  2x-3=16.

 

Kevin

Answer 2

2log₄(2x-3)=4

 

log₄(2x-3) = 2            [Divided both sides by 2]

 

4^log₄(2x-3) = 4²          [Raised everything as exponents to 4]

 

2x-3 = 16                   [ 4^log₄a = a, 4²=16]

 

Solve for x