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**log**_{4}(2x-3)=4-
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2**log**_{4}(2x-3)=4

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Another approach: 2log_{4}(2x-3)=4. Divide by 2: log_{4}(2x-3)=2.

Write in exponential form: log_{4}(2x-3)=2 becomes 4^{2}=2x-3.

solve: 2x-3=16.

Kevin

2log_{4}(2x-3)=4

log_{4}(2x-3) = 2 [Divided both sides by 2]

4^{log4(2x-3)} = 4^{2} [Raised everything as exponents to 4]

2x-3 = 16 [ 4^{log4a} = a, 4^{2}=16]

Solve for x