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2 Answers

We have a quadratic equation of the form  n^2+n/2-465=0. the solution of the quadratic is x=(-b±√(b^2-4*a*c))/2*a. the values will be a= 1; b= 1/2; c= -465. plugging this values we reach:
n= (-1/2±43.13)/2.
solve for n1 with plus sign and for n2 with the minus sign.