**log**

_{7(w2})+2

**log**

_{7}(5w)=2

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Brookline, MA

log_{7}(w^{2}) + 2log_{7}(5w) = 2

2log_{7}w + 2log_{7}(5w)=2

log_{7}w + log_{7}(5w)=1

log_{7}(5w^{2})=1

5w^{2}=7

w=±√(7/5)

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