3x^2+14x-5=0 solve quadratic fomula

Question

3x^2+14-5=0 I know the answer is 1/3, -5. But I have tryed and cannot get that. pleases show me the steps. i must be missing thank you so much

Answer 1

This is a very ugly one. Because the quadratic equation is not nice at all.

So try factoring, by first pulling out the leading 3:

3( x² + ^14x⁄₃  - ⁵⁄₃ ) ⇒ 3(x + 5 )( x - ¹/₃)   Not easy to arrive at, unfortunately

Answer 2

{(-14) + √[(14²)-(4)(3)(-5)]}/(2*3)= 2/6 = 1/3

 

1. square 14 = 196
2. multiply 4, 3, and -5 to get -60
3. subtract -60 from 196 = 196--60= 196+60= 256
4. take the square root of 256 = √256= 16

5. add 16 to -14 = 16 - 14=2
6. multiply 2 by 3 = 2*3 = 6
7. Divide 2 by 6 = 2/6 = 1/3

AND

{(-14) - √[(14²)-(4)(3)(-5)]}/(2*3)= -30/6 = -5

1. square 14 = 196
2. multiply 4, 3, and -5 to get -60
3. subtract -60 from 196 = 196--60= 196+60= 256
4. take the square root of 256 = √256= 16
5. subtract 16 from -14 = -14 -16=-30
6. multiply 2 by 3 = 2*3 = 6
7. Divide -30 by 6 = -30/6 = -5