If the perimeter of a rectangle is 64 inches squared and the area is 32 inches, what are the side lengths of that rectangle?

Question

If the perimeter of a rectangle is 64 inches squared and the area is 32 inches, what are the side lengths of that rectangle?

Answer 1

P=2l+2w

A=lw

32=2l+2w

16=l+w

16-w=l

64=lw

64=(16-w)(w)

64=16w-w^2

w^2-16w+64=0

(w-8)(w-8)=0

w-8=0

w=8 inches

you have a square 8 inches by 8 inches