Lauren W.

asked • 04/26/17

y^2(4y^2 + 17) = 15 #Solve the equations

y^2(4y^2 + 17) = 15 #Solve the equations

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Mark M. answered • 04/26/17

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y2(4y2 + 17) = 15
4y4 + 17y2 = 15
4y2 + 17y2 - 15 = 0
(4y2 - 3)(y2 + 5) = 0
 
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Lauren W.

I don't know what to do at (4y^2 - 3)(y^2 + 5)
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04/26/17

Lauren W.

I mean (4y^2 - 3)(y^2 + 5) = 0 that what I stuck with. 
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04/26/17

Mark M.

By the zero product rule
4y2 - 3 = 0
4y2 = 3
y2 = 3/4
y = ±√3 / 2\
Or
y2 + 5 = 0
y2 = -5
y = ±i √5
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04/26/17

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