(2sqrt 6a + 7) - 2a = 0 #solve the equation

Question

(2sqrt 6a + 7) - 2a = 0 #solve the equation

Answer 1

Lauren,

 

You need to use parentheses around the argument in the radical.  Assuming you meant

 

2 √(6a + 7) - 2a = 0,

 

then

 

√(6a + 7) = a

 

6a + 7 = a²

 

a² - 6a - 7 = 0

 

(a - 7)(a + 1) = 0

 

a = 7 or -1

Now test both solutions, and see that only a = 7 satisfies the original equation.

Answer 2

Hi Lauren,

Do you mean 2sqrt(6a+7)?