Gene G. answered 04/11/17
Tutor
5.0
(257)
You can do it! I'll show you how.
Let A, B and C be the weights of the coffees.
We have three equations. The first two are straightforward.
(1) A+B+C = 50
(2) C = 2A
Substitute 2A for C in (1)
(1) A+B+2A = 3A+B = 50
(4) B = 50-3A (We'll use this for substitution below.)
For the third equation, you can calculate the total retail value of the batch. Divide that by 50 and you get the retail value per pound.
(3) (15.99A+12.31B+12.76C) / 50 = 12.82
(3) 0.3198A+0.2462B+0.2552C = 12.82
Use equations (4) and (2) to substitute for B and C.
(3) 0.3198A+0.2462(50-3A)+0.2552(2A) =12.82
Solve for A
0.3198A+12.31-0.7386A+0.5104A = 12.82
0.0916A = 12.82-12.31 = 0.51
A = 5.568
Now use equations (4) and (2) to find B and C
(4) B = 50-3A = 50-(3)(5.568)
B = 33.297
(2) C = 2A = (2)(5.568)
C = 11.136
You can check the solutions by plugging the values into equations (1) and (3).
I did, and they agree with a small round-off error.