a diver scored 9.2,9.6,9.7,9.4 and 9.3 in the first 5 dives in a diving competition,

Question

where all scores are given in tenths. to win firdst place she must beat a total score of 56.6 what is the lowst score she can get on her last dive to win the comptition

Answer 1

Hi Thu, If the diver wants to beat 56.6, and the scores are given in tenths, then the diver has to get 56.7 to win. We know the diver's scores in 5 out of 6 dives. We can call the unknown dive score x. Then we have: A. 9.2+9.6+9.7+9.4+9.3+x=56.7 B. We add all the scores of the first 5 dives and get: 47.2+x=56.7 C. Now we subtract 47.2 from both sides to get x alone: x=9.5 So 9.5 is the lowest score she can get in order to beat 56.6. Hope that helps! -Sonja

Answer 2

9.2 + 9.6 + 9.7 + 9.4 + 9.3 = 47.2 (total she already has)

56.7 (= 56.6 + 0.1, the lowest possible winning score) - 47.2 = 9.5 (what she needs to win on final dive)