6 = sqrt 2z - 3 - 3 #solve the equations

Question

6 = sqrt 2z - 3 - 3 #solve the equations

Answer 1

First I think your question might be missing some parenthesis. Parenthesis are important because they tell you what to do first.

 

Now, as you wrote the problem, I would solve it like this

 

6 = sqrt(2z) -3-3

6 = sqrt(2z) -6

12 = sqrt(2z)

12^2 = [sqrt(2z)]^2

144 = 2z

144/2 = 2z/2

72 = z

 

But I am guessing that your question was most likely

6 = sqrt (2z-3) -3

the difference between the two is that in the first  we have only the square root of 2z, in the second we have the squareroot of 2z -3.

 

This is how you would solve it

6 = sqrt (2z-3) -3  (add 3 to both sides)

9 = sqrt(2z-3)  (square each side)

81 = 2z - 3 (add 3 to both sides)

84 = 2z (divide both sides by 2)

42 =z