
Kemal G. answered 04/06/17
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Hi Gautam,
x^3 + ax^2 + a^2x - b^3 = 0
rewrite as
ax^2 + a^2x + x^3 - b^3 = 0
ax(x+a) + x^3 - b^3 = 0
x^3 - b^3 is the difference of two cubes and can be factored as
x^3 - b^3 = (x-b)(x^2+xb+b^2)
then, the final form is
ax(x+a) + (x-b)(x^2+xb+b^2) = 0
Gautam H.
04/08/17