Sqrt 128x^9y^16/[16x^2y]? #Simplify

Question

Sqrt 128x^9y^16/[16x^2y]? #Simplify

Answer 1

Hi Lauren, the √((128x⁹y¹⁶)/(16z²y)) can be broken into three parts, the coefficients, the x terms, and the y terms.

 

coefficients:

 

128/16 = 8

 

√8 = √(2² * 2), or 2√2

 

x terms:

 

x⁹/x² = x⁷

 

√x⁷ = √((x³)² * x), or x³√x

 

y terms:

 

y¹⁶/y = y¹⁵

 

√y¹⁵ = √((y⁷)² * y), or y⁷√y

 

Now put them all back together:

 

2x³y⁷√(2xy)

 

Questions?