Find three consecutive odd integers such that the product of the first and third is 71 more than 10 times the second.

Question

Solve the problem

Answer 1

x(x + 4) = 10(x + 2) + 71

x² + 4x = 10x + 20 + 71

x² - 6x - 91 = 0

(x + 7)(x - 13) = 0

 

x + 7 = 0

x = -7

 

-7, -5, -3

 

x - 13 = 0

x = 13

 

13, 15, 17