
Gene G. answered 03/11/17
Tutor
5.0
(257)
You can do it! I'll show you how.
I think Michael misread the problem.
It's going to be a little more messy!
The shorter path saves half the length of the longer side.
X = the diagonal walked
L = The longer side
156 = the shorter side.
The long route is L + 156.
Subtracting the shortcut distance, we get an expression for the distance saved.
L + 156 - X
That is half the length of the longer side, so:
L + 156 - X = L/2
Using the Pythagorean theorem, we get an expression for the diagonal X:
X = √(L2+1562)
Substitute this for X above.
L + 156 - √(L2+1562) = L/2
Isolate the radical on one side, then square both sides.
L - L/2 + 156 = √(L2+1562)
(L/2 + 156)2 = L2 + 1562
L2/4 +156L + 1562 = L2 +1562
0 = L2 - L2/4 - 156L
3L2/4 - 156L = 0 (I swapped sides, too.)
L(3L/4 - 156) = 0
L = 0 Doesn't make sense. Ignore it.
3L/4 - 156 = 0
L = 4/3 (156) = 208
Check:
X = √(1562 + 2082) = 260 shortcut
156 + L = 156 + 208 = 364 long route
364 - X = 364 -260 = 104
The savings is half of L.

Gene G.
03/11/17