
Stephen M. answered 03/11/17
Tutor
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Ivy League Graduate - Math, Computer Science, and Business Tutor
Let:
A1 = cash B1 = price > $50
A2 = credit card B2 = price <= $50
A3 = debit card
Probabilities:
P(A1) = 0.26
P(A2) = 0.20
P(A3) = 0.54
Conditional Probabilities:
P(A1 | B1) = 0.20
P(A2 | B1) = 0.85
P(A3 | B1) = 0.60
Find P(A1| B1) using Bayes' Theorem:
P(A1 | B1) = [P(A1) * P(A1|B1)] / [P(A1) * P(A1|B1) + P(A2) * P(A2|B1) + P(A3) * P(A3|B1)]
=[0.26 * 0.20] /[ 0.26 * 0.20 + 0.20 * 0.85 + 0.54 * 0.60]
= 0.052 / 0.052 + 0.17 + 0.324
= 0.052 / 0.546
= 0.095