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asked 03/02/17The height h (in feet) above the water of a cliff diver is modeled by h=−16t^+8t+80, where t is the time (in seconds). How long is the diver in t
If you could help me solve this question that would be great!
Thank you!
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1 Expert Answer
Jason W. answered 03/02/17
Tutor
4.8
(4)
Georgia Tech PhD student for Physics and Statistics
I'm assuming you are asking how long is the diver in the air before hitting the water below. I also assume the equation is:
h = -16t2 + 8t + 80
So, factor out the GCF and factor the polynomial
h = 8*(-2t2 + t + 10)
h = 8*(-2t + 5)*(t + 2)
At t=0 the diver is at the top of the cliff, or h = 80 feet. At the bottom of the cliff, h = 0 feet. So,
0 = 8*(-2t + 5)*(t + 2)
Solve for t and remember that time can't be negative.
-2t + 5 = 0
t + 2 = 0
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Debdatta B.
03/02/17