can you show me step by step using the quadratic formula to solve 3v^2+4v-1=0. Also how to recheck answer step by step.

To solve by quadratic formula you must first make sure all the terms are on one side of the equation and it is set equal to zero. Also make sure the terms are arranged from highest power to lowest.

The coefficient (number) in front of the first term is a

The coefficient (number) in front of the second term is b

The coefficient (number) in front of the third term is c

For this problem 3V

^{2}+4V -1 =0 a= 3 b= 4 and c= -1_{ __________}

Use the formula -b +/- √ b

^{2 }- 4ac 2a

____________

This gives you -4 +/- √(4)

^{2 }- 4(3)(-1) 2(3)

_________ _______

-4 +/- √ 16 - (-12) ⇒
-4 +/- √ 16 +12

6 6

___

-4 +/- √ 28 ( 28 can be factored into 4 times 7 and 4 is a perfect square that comes

6 out to the front of the radican as a 2)

__

-4 +/- 2√ 7

6

___ ____

-4 +/- 2√ 7 ⇒ -2 +/- √ 7

6 6 3 3