The length of a rectangle is 3 times the width. The Perimeter is 44cm. What are the dimensions of the rectangle?

Question

Please help me understand the problem. I have no idea what this means. I also don't know what I'm supposed to write in this box.

Answer 1

Hi Jon, you need to find the length and width of the rectangle. Let l represent the length and w represent the width. Use the equation for the perimeter of a rectangle, p = 2l + 2w to solve the question.

 

Given:

 

p = 44cm

 

l = 3 * w

 

Substitute:

 

2l + 2w = p

 

2(3w) + 2w = 44

 

6w  + 2w = 44

 

8w = 44

 

w = 5.5

 

l = 3w = 3 * 5.5

 

l = 16.5

 

The length of the rectangle is 16.5 cm and the width of the rectangle is 5.5 cm.

 

Check:

 

2l + 2w = p

 

2 * 16.5 + 2 * 5.5 = 44

 

33 + 11 = 44

 

44 = 44

 

Values check.

 

Questions?

 

 

Answer 2

Perimeter of a rectangle:  P = 2L + 2W = 2(L+W)

 

L = 3W

2(L+W) = 44

 

2(3W+W) = 44

2(4W) = 44

8W = 44

 

W = 44/8 = 11/2 = 5 1/2 cm

 

L = 3W = (11/2)(3) = 33/2 = 16 1/2 cm

Answer 3

w=width

3w=length

P=2l+2w

44=2(3w)+2(w)

44=6w+2w

44=8w

w=44/8

w=5.5 cm

l=3*5.5=16.5 cm