Michael C. answered 02/09/17
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Draw a right triangle
length of base =2b; length of other side be 2h
3^2*17 = h^2 + (2b)^2
153 = h^2 + 4b^2
6^2*2 =(2h)^2 + b^2
72 = 4h^2 + b^2
solving both equations simultaneously; gives h = 3 and b = 6
(Hypothenuse)^2 = (2b)^2 + (2h)^2 = 12^2 + 6^2
hypothenuse = 180^1/2 = 6*5^1/2 = 13.4