"{2^(3x-1) +10}/21=18"

Question

(2^3x-1 + 10)/21 = 18

 

Answer 1

Multiply both sides of the equation by 21.

 

2^{3x - 1} + 10 = 278

 

 

Subtract 10 on both sides of the equation.

 

2^{3x - 1} = 268

 

 

Log both sides of the equation and bring all exponents as the coefficient of logs.

 

(3x - 1)Log(2) = Log(268)

 

3x - 1 = Log(268) / Log(2)

 

3x = [Log(268) / Log(2)] + 1

 

   x = (1/3) * [(Log(268) / Log(2)) + 1]