
Andrew M. answered 02/06/17
Tutor
New to Wyzant
Mathematics - Algebra a Specialty / F.I.T. Grad - B.S. w/Honors
First, let's set some variables:
Let b = # candy bars Bill sold
Let cb = price Bill charged
Let j = # candy bars Jill sold
Let cj = price Jill charged
Bill generated $176 revenue... # bars times price per bar:
b(cb) = 176 __________________ eqn 1
Jill charged 15 cents or $0.15 less than Bill per candy bar:
cj = cb - 0.15 _______________ eqn 2
Jill generated $2 less revenue than Bill or $174:
j(cj) = 174 __________________ eqn 3
Jill sold 10 more candy bars than Bill:
j = b + 10 ___________________ eqn 4
Combining for total revenue:
b(cb) + j(cj) = 174 + 176
b(cb) + j(cj) = 350
substituting from eqn 4, j = b+10
and from eqn 2, cj = cb - 0.15
b(cb) + (b+10)(cb-0.15) = 350
bcb + bcb - 0.15b + 10cb - 1.5 = 350
combine like terms and add 1.5 to both sides
2bcb + 10cb - 0.15b = 351.5
From eqn 1: bcb = 176
2(176) + 10cb - 0.15b = 351.5
352 + 10cb - 0.15b = 351.5
10cb - 0.15b = -0.5
Also from eqn 1 we can get cb = 176/b
10(176/b) - 0.15b = -0.5
Multiply through by b
1760 - 0.15b2 = -0.5b
Move all to one side of equal sign
add (0.15b2 -1760) to both sides
0.15b2 -0.5b - 1760 = 0
To clear decimals multiply through by 100
15b2 - 50b - 176000 = 0
From quadratic formula:
b = [50 ± √((-50)2-4(15)(-176000))]/[2(15)]
b = [50 ± √10562500]/30
b = (50 ± 3250)/30
Disregarding the negative since Bill did not sell a negative
number of candy bars
b = 3300/30 = 110 candy bars
bill sold 110 candy bars
jill sold 110 + 10 = 120 candy bars
bcb = 176
110cb = 176
cb = 176/110 = $1.60
Bill charged $1.60 per candy bar
Jill charged 0.15 less per candy bar
Jill charged $1.45 per candy bar

Andrew M.
02/06/17