Arthur D. answered 01/30/17
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n and n+2 are the integers
n(n+2)=5(n+2)
n^2+2n=5n+10
n^2+2n-5n-10=0
n^2-3n-10=0
(n-5)(n+2)=0
n-5=0
n=5
n+2=7
n+2=0
n=-2
n+2=0
there are two solutions: 7 and 5 is one solution and 0 and -2 is another solution