
Michael C. answered 01/27/17
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B is the best answer.
NB; in case you are solving a quadratic equation like this, assuming the expression above is equal to some constant like zero, one method would be:
Let n^1/3 be equal to x (meaning n = x^3)
Rewriting the same we get; 2x^2 -3x +5 = (whatever the constant is)
Then cube the values you obtain for x to obtain the values for n.