How does P(X<= a) + P(X > a) = 1 becomes [P(X <= a) >= 1?

Question

I would have to include pictures for it.

Answer 1

Indeed, for probabilities distribution, P(X<= a) + P(X > a) = 1, by definition.

 

My guess is that Ray simply wants  

 P(X > a) = 1 - P(x≤a), which follows from a simple algebraic step.