Susan B.

asked • 09/03/12

i need help with my homework

f(x) = x^2 - 3x  find f(-8)

 

P(T)=4t -5 Find P(T-2)

G(A)=3^3a-2: Find G(1)

G(X) =3x -3 : Find G(-6)

H(T) =2times 5^-t-1. Find H(-2)

G(A)=4a: Find G(2a)

 

3 Answers By Expert Tutors

By:

Jordan K. answered • 11/12/12

Tutor
4.9 (79)

Nationally Certified Math Teacher (grades 6 through 12)

David F. answered • 09/03/12

Tutor
4.7 (19)

Best Math Tutor in the Galaxy

Susan B.

Thank you, but I still don't understand. I am about to give up!

Report

09/03/12

David F.

I'm assuming you're encountering this problem in an algebra class?  The first time you see functions, they don't make any sense, and they're probably not going to for some time.  You may find it easier for now to just accept that there are things here that won't make sense, and it's ok for them not to.  Algebra is a skills class, you don't learn anything useful about the universe.  Now, when you go and take a physics class, you do more intense algebra than you've ever done AND you learn about the world.  But here, now, this thing doesn't have to make sense.

The only thing that has to make sense right now is this: f(x) means that for every place you see an x, you can put anything you want instead of the x.  Here are some examples:

f(x) = x + 1

f(y) = y + 1  (replace with a y)

f(anything) = anything + 1

f(dinner) = dinner + 1

See?  So when it's a number, like you have here, you just replace with the number.  After that, a simple computation will turn it into a single number, and you have a value.

So, f(-8) = (-8)2 - 3(-8)

Not too long ago I'm sure you did some linear equations and parabolas (the dreaded quadratic, complete with the quadratic equation).  So you looked at something like this:

y = 5x + 6  (linear equation)

You recall, hopefully, that that represents a line with a y-intercept at 6 and a slope of 5?  Well, for a function, just replace y with f(x), like so:

f(x) = 5x + 6

Previously, you would make a chart like this to graph the line:

x  |  y

0  |  6

1  |  11

-6 |  0

Now, after you've changed y to f(x), you'll do the same thing, like so:

x | f(x)

0 | 6

1 | 11

-6 | 0

Changing the notation looks like it's just a bunch of silliness, and I have to admit the first time I encountered functions, I thought they were just silly.  And all the words around them just make it hopelessly complicated for no good reason, especially considering that linear equations worked fine without all that jargon, right?

In calculus, you'll study functions in depth and learn very rigorous tools and methods to study how they change.  For every calculus student, there's an "aha!" moment when they feel like they've learned something fundamental about how the universe works.

But that happens in calculus.  By then, you'll have studied functions in algebra, trigonometry, and precalculus.  That's what it takes for them to finally make sense.  So, they're introduced in the curriculum here so you can start to learn how to use algebra to work with them, but full understanding isn't available for a little while longer.

That's one of the things that makes algebra so tough: there are quite a few topics that don't make any sense until you see them in a different context in a different class.

So keep your head up!

Does this help?

Report

09/03/12

Still looking for help? Get the right answer, fast.

Ask a question for free

Get a free answer to a quick problem.
Most questions answered within 4 hours.

OR

Find an Online Tutor Now

Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.