
Steve S. answered 02/09/14
Tutor
5
(3)
Tutoring in Precalculus, Trig, and Differential Calculus
f(x)= 1/x
Can't divide by zero, so x = 0 is a vertical asymptote.
As x → ±∞, f(x) → 0±, so y = 0, the x-axis, is a horizontal asymptote.
f(x)= x^3/(x^2-1) = x + x/(x^2-1) by long division
Can't divide by zero, so x = ±1 are vertical asymptotes.
As x → ±∞, f(x) → x, so y = x is a slant asymptote.
As x → ±∞, f(x) → x, so y = x is a slant asymptote.
f(x)=x^3/(x^2+1) = x - x/(x^2+1) by long division
x^2+1 > 0 for all real numbers => no vertical asymptotes.
As x → ±∞, f(x) → x, so y = x is a slant asymptote.