Manisha S. answered 12/11/16
Tutor
5.0
(245)
Expert in All Things Algebra
We are given the average speed (15 mi/h) and the time it takes to get to campus using that speed (2.25 h). Since time is inversely related to speed (v=d/t) we can plug in the values to find the distance to campus.
15 mi/h = x / 2.25 h
x=33.75 mi
Now that we know the distance, we can plug it in along with the new speed (45 mi/h) to find the new time.
45 mi/h = 33.75 mi / x
x=33.75 / 45 mi h
x = 0.75 h