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# They need to buy 25 more chairs than stools The chairs cost \$32 each the stools cost \$28 each budget is \$2,620, how many chairs can they buy?

I need the answer for my brother i couldn't figure it out.

### 2 Answers by Expert Tutors

Vivian L. | Microsoft Word/Excel/Outlook, essay composition, math; I LOVE TO TEACHMicrosoft Word/Excel/Outlook, essay comp...
3.0 3.0 (1 lesson ratings) (1)
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Hi Natalia;
stools...x, \$28/stool
chairs...x+25, \$32/chair
budget...\$2,620
\$2620=[(\$32)(x+25)]+[(\$28)(x)]
\$2620=\$32x+\$800+\$28x
\$2620=\$60x+\$800
Let's subtract \$800 from both sides...
\$2620-\$800=\$60x+\$800-\$800
\$1820=\$60x
Let's divide both sides by \$60...
\$1820/\$60=(\$60x)/\$60
30=x
30+25=x+25
They can purchase 30 stools, 55 chairs, and will have \$20 remaining.
Arthur D. | Effective Mathematics TutorEffective Mathematics Tutor
4.8 4.8 (13 lesson ratings) (13)
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let x=# of stools
let x+25=# of chairs
\$28*x+\$32*(x+25)=\$2620
28x+32x+800=2620
60x+800=2620
60x=1820
x=1820/60
x=30.333...
You can buy 30 stools and 55 chairs.
30*\$28+55*\$32=\$840+\$1760=\$2600 with \$20 left over